10x^2+55x+25=0

Solution for 10x^2+55x+25=0 equation:

10x^2+55x+25=0

a = 10; b = 55; c = +25;
Δ = b2-4ac
Δ = 552-4·10·25
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-45}{2*10}=\frac{-100}{20}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+45}{2*10}=\frac{-10}{20}
=-1/2
$